x^2+54x-168=0

Solution for x^2+54x-168=0 equation:

x^2+54x-168=0

a = 1; b = 54; c = -168;
Δ = b2-4ac
Δ = 542-4·1·(-168)
Δ = 3588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3588}=\sqrt{4*897}=\sqrt{4}*\sqrt{897}=2\sqrt{897}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-2\sqrt{897}}{2*1}=\frac{-54-2\sqrt{897}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+2\sqrt{897}}{2*1}=\frac{-54+2\sqrt{897}}{2}
$